View Full Version : Pythagorean Theorem Question
Mr. Apollo
01-31-2006, 04:35 PM
I know this is extremely simple, but it's (literally) been at least 10 years since I had to do stuff like this so please bear with me.
I know that a^2+b^2=c^2.
In the case I'm looking at a and b are in a ratio of 3:4 so that 3^2+4^2=c^2.
In the case where c^2=1296 [c=36] what are a and b?
Roman
01-31-2006, 04:53 PM
a = 21.6 b = 28.8
If 3 represents side a, 4 represents side b and 5 for side c (since this is a 3-4-5 triangle), then use the ratio of (3/5)*36 to give you a and (4/5)*36
to get the values of a and b if c = 36.
Mr. Apollo
02-01-2006, 11:46 PM
Cool, thanks.
Darn that Pythagorus and his crazy theorums, always causing trouble.
tsehou
02-04-2006, 07:08 PM
His theorem only works with right angle triangles.
Ottawaman
02-04-2006, 07:10 PM
His theorem only works with right angle triangles.
probably a conservative :D
Custer
02-04-2006, 09:25 PM
I could be wrong but is it not C= (a^2 + B^2)
C^2 = a^2 + b^2
C = root(a^2 + b^2)
Aristera
02-05-2006, 03:24 AM
If you use the full formula you can work out any triangle.
C^2 = A^2 + B^2 - 2AB cos(c)
In a right angle triangle cos(90) = 0 so you don't need the last part as it will always = 0
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